![]() ![]() Main reason of that behavior is because they are bonded * using static binding in Java. Access to private fields: To access private fields, you need to call the class.getdeclaredfield (String name) or the class.getdeclaredfields method. But with the reflect, it is absolutely possible. ** * Java Program to demonstrate, private method can not be overridden in Java, * not even on Inner classes. You can not access the method or field when it is private in the usual way, java compiler does not allow that. By the way, compiler will not complain, it will treat method with exact same signature in child class as separate method, and this is known as method hiding in Java. Had the private method overridden that it would have called method from child class. ![]() #RUN PRIVATE METHOD JAVA REFLECTION CODE#Anyway, this will also not work because private methods are bonded during compile time and only Type (or Class) is used to locate a private method.įor Example in below code where it looks like that nested class is an overriding private method, but if you call privateMethod() with a type of super class but the object of the subclass, it will only execute privateMethod() declared in the parent class, which is not exactly method overriding. By the way, one more possibility of overriding private methods in an inner class, since private methods are accessible in an inner class, and that’s why it is one of the tricky java interview questions. Since method overriding can only be done on derived class and private methods are not accessible in a subclass, you just can not override them. We have use getDeclaredMethod() to get private method and turn off access. No, you cannot override private methods in Java, private methods are non-virtual in Java and access differently than non-private one. Answer (1 of 15): Use code setAccessible(true)/code on your Method object before using its code invoke/code method. The invoke() method is used to call public method in java using reflection API. ![]()
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